Question

find the smallest number by which 9048​

Answer 1

Answer:

Solution :-

To find the smallest number by which 9408 must be divided so that the quotient is a perfect square, we have to find the prime factors of 9408.

9408 = 2*2*2*2*2*2*3*7*7

Prime factors of 9408 are 2, 2, 2, 2, 2, 2. 3, 7, 7

Out of the prime factors of 9408, only 3 is without pair.

So, 3 is the number by which 9408 must be divided to make the quotient a perfect square.

9408/3 = 3136

Square root of 3136

56

_____________

5 | 3136

5 | 25

___ |______

106 | 636

6 | 636

|_______

| 000

So, √3136 = 56

Answer.

I hope this answers you help it

Answer 2

Answer:

The smallest whole number to be divided = 3

and square root of new number = 56.