find the smallest number by which 9408 must be devided so that it becomes perfect sqaure
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hi friend :
prime factors of 9408 are : 2*2*2*2*2*2*3*7*7
pairs are =2*2*2*7
since 3 is unpaired so 94080 should be divided by 3 to get a perfect square
verification :
9408/3 =3136 and the square root of 3136 is 56
hope i helped you
pls mark it as brainliest answer because i have done the verification also for you
prime factors of 9408 are : 2*2*2*2*2*2*3*7*7
pairs are =2*2*2*7
since 3 is unpaired so 94080 should be divided by 3 to get a perfect square
verification :
9408/3 =3136 and the square root of 3136 is 56
hope i helped you
pls mark it as brainliest answer because i have done the verification also for you
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