find the smallest number by which 9408 must be divided so that it becomes a perfect square also find the square root of the number so obtained
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The no. which should be divided to 9408 so as to make it a perfect square is 3.
The no. so obtained is 3136 and its square root is 56.
Here are the steps
9408 = 2×2×2×2×2×2×3×7×7
Sinve 3 is not in a pair so it must be divided to 9408 to obtain a perfect square.
9408÷3 = 3136
3136 = 2×2×2×2×2×2×7×7
root 3136 = 2×2×2×7
2×2×2×7 = 56
so 56 is the answer.
Hope it helps you. Plz mark it as brainliest if you found the answer helpful.
The no. so obtained is 3136 and its square root is 56.
Here are the steps
9408 = 2×2×2×2×2×2×3×7×7
Sinve 3 is not in a pair so it must be divided to 9408 to obtain a perfect square.
9408÷3 = 3136
3136 = 2×2×2×2×2×2×7×7
root 3136 = 2×2×2×7
2×2×2×7 = 56
so 56 is the answer.
Hope it helps you. Plz mark it as brainliest if you found the answer helpful.
vanishchopra123:
please give it step by step
I gave u the steps. Hope it helps you
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