Question

find the smallest number by which 9408 must be divided so that it become a perfect square also find the square root of the perfect square so obtained

plz answer it fast

Answer 1

heya
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[ first of all we need to find the prime factors of 9408 ]

Prime Factors of 9408
= 2×2×2×2×2×2×7×7×3

Smallest no. to divided = 3
[ as 3 is not is pair ]

So, 9408/3 = 2×2×2×2×2×2×7×7×3/3

♦ √3136
= √2×2×2×2×2×2×7×7
= 2×2×2×7
= 56

♢ Perfect sq. = 3136

♢ Sq. root of Perfect sq. = 56
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I hope this answer helps you !