Question

Find the smallest number by which 9408 must be divided so it becomes a perfect cube.​

Answer 1

9408 = 2 X 2 X 2 X 2 X 2 X 2 X 7 X 7 X 3

• We observe that prime factor 3 does not form a pair.

Therefore,

• we must divide the number by 3 so that the quotient becomes a perfect square.

$\therefore \: \: \frac{9408}{3} = 3136$

3136 = (2 x 2) × (2 x 2) (2 x 2) × (7 x 7)

Now,

• each prime factor occurs in pairs.

Therefore,

• the required smallest number is 3.

$\implies{ \sqrt{3136} = 2 \times 2 \times 2 \times 7}$

= 56

Answer 2

Hey mate here is your answer ⬇️ ⬇️

Refer to the attachment.