find the smallest number by which 9408 must be divided to get a perfect square with fully prime factorization method
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First do the prime factorization and then make pair and in them one is odd so that no. Is answer
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since
The pairs are 2×2×2×7
& the unpaired no. is 3
so the smallest no. by which 9408 must be divided is 3.
The pairs are 2×2×2×7
& the unpaired no. is 3
so the smallest no. by which 9408 must be divided is 3.
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