Question

Find the smallest number by which a number ‘n’ written as p2q 4 r 3 (where p,q,r are the prime factors) must be divided so that the quotient becomes a perfect square. Also find the square root of square number so obtained.​

Answer 1

Answer:

216=

2×2

×2×

3×3

×3

Here, pair of 2 and 3 is not completed.

So, 216 is not a Perfect Square.

The number should be divided by 2×3 to make it a perfect square.

216÷6=36

Factors of 36 = 2×2×3×3 which is the perfect square of 2×3=6.

Now, 36 is a perfect square. Hence, the smallest number 6 should divide 216 so that the quotient is a perfect square.

Answer 2

Answer:

Hope the attachment helps you dear .