find the smallest number by which each of the following numbers must be multina
to obtain a perfect cube.
(iv) 675
(i) 243
(ii) 72
(ii) 256
(V) 100
3. Find the smallest number by which each of the following numbers must be divided
obtain a perfect cube.
() 81
(ii) 128
(iii) 135
(iv) 192
(v) 704
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Answer:
first question the answer is 243 can be a perfect square by multiplying five times with 2 and second question 81 is the smallest by 9 and 9 is also a square root of 3
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