Math, asked by keahav8368, 11 months ago

find the smallest number by which each of the following number should be divided so as to get a perfect square also find the square root by the square number thus obtained [a] 768​

Answers

Answered by suresh34411
4

Answer:

3

Step-by-step explanation:

By prime factorisation of 768, we get

768 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 3

Here, 2 are in pair, but 3 needs a pair to make 768 a perfect square.

So, 768 needs to be multiplied by 3 to become a perfect square.

Hence, Answer = 3

Answered by pjahnabi007
1

Step-by-step explanation:

768= 2×2×2×2×2×2×2×2×2×3

Here, 2 are in pair, but 3 needs a pair to make 768 a perfect square.

So, 768 needs to be multiplied by 3 to become a perfect square.

Hence, Answer = 3

square no. = 768x3=2304

square root of 2304-48

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