Question

find the smallest number by which each of the following numbers must be multiplied to obtain a perfect cube 243​

Answer 1

Answer:

243=3×3×3×3×3

Number of 3's is 5, so we need to another 3 in the factorization to make 243 a perfect cube. 243 multiplied by 3 will be a perfect cube

Answer 2

Answer:

Prime factors of 243=3×3×3×3×3

Here 3 does not appear in 3's group.

3|243

3|81

3|27

3|9

3|3

|1

Therefore, 243 must be multiplied by 3 to make it a perfect cube.