find the smallest number by which each of the following number must be multiplied to obtain a perfect cube. Also find the cube root of the number so obtained 256
find the smallest number by which each of the following numbers by must be multiplied to obtain a perfect cube. also find the cube of the number so obtained
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Step-by-step explanation:
prime factorisation of 256 =
2*2*2*2*2*2*2*2
-------. -------
when we try to make groups of three 2s. one group remains incomplete as one 2 is short. so we need to multiply 256 by 2 to make it a perfect cube.
the number would become 256*2 = 512
and it's cube root will be = 2*2*2 = 8
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