Find the smallest number by which each of the following numbers must be multiplied to obtain a perfect cube
1 243
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1
Answer:
is there is any mistake in this question
I mean the arrangement of the numbers.....
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6
Answer:
Prime factors of 243= 3×3×3×3×3
Here 3 does not appear in 3's group.
3|243
3|81
3|27
3|9
3|3
|1
Therefore, 243 must be multiplied by 3 to make it a perfect cube.
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