Math, asked by juvenxeviour18, 2 months ago

find the smallest number by which each of the following numbers must be divided to obtain a perfect cube (1) 128​

Answers

Answered by pramodskaduskar05
1

Step-by-step explanation:

Find the smallest number by which each of the following numbers must be divided to obtain a perfect cube:

(i)81

(ii)128

(iii)135

(iv)192

(v)704

Solution:

(i)81

Prime factors of 81 = 3\times3\times3\times33×3×3×3

Here one factor 3 is not grouped in triplets.

Therefore 81 must be divided by 3 to make it a perfect cube.

Answered by jitendrakalson30
1

Answer:

2

Step-by-step explanation:

128÷2 = 64

and 64 is the cube of 4

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