Question

find the smallest number by which each of the following number must be divided to obtain a perfect cube. also find the perfect cubes of 6860?​

Answer 1

Answer:

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Step-by-step explanation:

Prime factorising 68600, we get,

68600=2×2×2×5×5×7×7×7

=2

3

×5

2

×7

3

.

We know, a perfect cube has multiples of 3 as powers of prime factors.

Here, number of 2's is 3, number of 5's is 2 and number of 7's is 3.

So we need to multiply another 5 in the factorization to make 68600 a perfect cube.

Hence, the smallest number by which 68600 must be multiplied to obtain a perfect cube is 5.