find the smallest number by which each of the following numbers must be multiplied to obtain a perfect cube 243
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243=3×3×3×3×3
3 is not in the pair, so 243 should be multiplied by 3 to make it a perfect cube.
Hope it helps:)
3 is not in the pair, so 243 should be multiplied by 3 to make it a perfect cube.
Hope it helps:)
Answered by
9
Answer:
1. 243
=Prime factors of 243 = 3×3×3×3×3
=Here 3 does not appear in 3's group.
3|243
3|81
3|27
3|9
3|3
|1
Therefore, 243 must be multiplied by 3 to make it a perfect cube.
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