Find the smallest number by which each of the following numbers must be multiplied to obtain a perfect cube
(i) 243
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0
Answer:
3
Step-by-step explanation:
Prime factorizing 243, we get,
243=3×3×3×3×3=3
5
.
We know, a perfect cube has multiples of 3 as powers of prime factors.
Here, number of 3's is 5.
So we need to multiply another 3 in the factorization to make 243 a perfect cube.
Hence, the smallest number by which 243 must be multiplied to obtain a perfect cube is 3.
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