Question

Find the smallest number by which each of the following numbers must be multiplied to obtain a perfect cube. (i) 243 (ii) 256​

Answer 1

Answer:

(i) 243

Prime factors of 243 =

Here 3 doesn't appear in 3's group.

So, 243 must be multiplied by 3 to make it perfect cube.

(ii) 256

Prime factors of 256= 2×2×2×2×2×2×2×2

Here one factor 2 is required to make a 3's group.

So, 256 must be multiplied by 2 to make it perfect cube.

hope it helps you.

Answer 2

Answer:

(i) 243.

3 must be multiplied by 243 to make its perfect cube.

(ii) 256 .

must be multiplied by 256 to make its perfect cube.

$thank \: you$