Find the smallest number by which each of the following must be multiplied / divided to get a perfect cube(i) 135 ii) 1125
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Answer:
1)135
By Prime factorization we get
135=5×3×3×3
Clearly, to make it a perfect cube it must be divided by 5.
And to make it a perfect cube it must be multiplied by (5×5)=25
2)1125
By Prime factorization we get
1125=5×5×5×3×3
Clearly, to make it a perfect cube it must be divided by (3×3)=9
And to make it a perfect cube it must be multiplied by 3
Step-by-step explanation:
Hope it helps.......
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