Find the smallest number by which each of the following must be multiplied and divided to obtain a fefect cube...... a) 675....
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27 is answer of question
yadavomkar:
sorry 15 or 45 or 5 may be right
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hye
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we have to Find the smallest number by which each of the following must be multiplied and divided to obtain a fefect cube...... a) 675....
so lets find the prime factorisation of 675
prime factorisation of 675 = 3 x 3 x 3 x 5 x 5
=>![\sqrt675} = \sqrt3 ^{2}* \sqrt{3} * \sqrt{5 ^{2} } } \sqrt675} = \sqrt3 ^{2}* \sqrt{3} * \sqrt{5 ^{2} } }](https://tex.z-dn.net/?f=+%5Csqrt675%7D++%3D++%5Csqrt3+%5E%7B2%7D%2A++%5Csqrt%7B3%7D+%2A+%5Csqrt%7B5+%5E%7B2%7D+%7D+%7D+)
we see that 3 is not in pair
=>∴ 3 is the smallest number divided/multiplied to 675 to make perfect square
=>3 ×675 = 2025
=>√2025 = 45
=> 675 ÷3 = 225
=>√225 = 15
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hope it helps u
============================
we have to Find the smallest number by which each of the following must be multiplied and divided to obtain a fefect cube...... a) 675....
so lets find the prime factorisation of 675
prime factorisation of 675 = 3 x 3 x 3 x 5 x 5
=>
we see that 3 is not in pair
=>∴ 3 is the smallest number divided/multiplied to 675 to make perfect square
=>3 ×675 = 2025
=>√2025 = 45
=> 675 ÷3 = 225
=>√225 = 15
====================
hope it helps u
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