find the smallest number by which must be divided to get perfect cube
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Find the smallest number by which each of the following numbers must be divided to obtain a perfect cube
(i) 81 (ii) 128 (iii) 135 (iv) 192 (v) 704
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Solution:
A number is a perfect cube only when each factor in the prime factorization is grouped in triples. Using this concept, the smallest number can be identified.
(i) 81
Class 8 Maths Chapter 7 Exercise 7.1 Question 3
81 = 3 × 3 × 3 × 3
= 33 × 3
Here, the prime factor 3 is not grouped as a triplet. Hence, we divide 81 by 3, so that the obtained number becomes a perfect cube.
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Step-by-step explanation:
3 is the prime factors that have been given a square is 10 cm then the diagonal is 10 cm then the diagonal is 62827646473727373 bxhxhcudjjs
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