find the smallest number by which of the given number must be multiplied so that the product is a perfect square (a)512 (b)700 (c) 1323 (d) 35280
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First find the prime factors of 1323
1323=3×441
=3×3×147
=3×3×3×49
=3×3×3×7×7
3×3×3×7×7 are they prime factors of 1323
now form pairs of two same numbers which number remains only one is your answer
means here you have to multiply 1323 by 3
now similarly find prime factors of 35280
35280=2×17640
=2×2×8820
=2×2×2×4410
=2×2×2×2×2205
=2×2×2×2×3×735
=2×2×2×2×3×3×245
=2×2×2×2×3×3×5×49
=2×2×2×2×3×3×5×7×7
here 5 left alone so your answer is 5
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