Question

find the smallest number by which the following must be multiplied to make them perfect cube 2560

Answer 1

First, prime factorise it
2560= 2^9 x 5
therefore, 2^9=2^3*2^3
so it can be taken as a perfect cube
but 5 is not in a pair of 3
so to make 5 to 5^3, we need to multiply it by 5*5
Therefore the smallest no. that should be multiplied will be 25
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