Question

find the smallest number by which the following number must be divided to make the quotients perfect cube 54​

Answer 1

Answer:

54 = (2^1)(3^3)

We have to make all powers of the prime factors a multiple of 3 because:

(2^(3a))(3^(3b))

= [(2^a)(3^b)]^3

Which is a perfect cube.

Therefore we have to divide 54 by 2 to make the power of the ‘2’ be 0

So the answer is 2

hope this will be helpful to

please follow me as it will motivate me to give my best to u all only if u like by answer

Answer 2

hope it will hlp uhh dude...