Find the smallest number by which the given number must be divided so that the resulting number is a perfect square:
a) 1800
b)14283
c)2904
Answers
Answered by
26
heya
_______________________________
[ first of all we need to find the prime factors of the numbers ]
ⓐ 1,800
Prime Factors of 1,800
= 5×5×3×3×2×2×2
Smallest no. to be divided = 2
[ as 2 is not in pair ]
So, 1,800/2 = 5×5×3×3×2×2×2/2
♦ √900
= √5×5×3×3×2×2
= 5×3×2
= 30
♢ Perfect sq. = 900
_______________________
ⓑ 14,283
Prime factors of 14,283
= 23×23×3×3×3
Smallest no. to be divided = 3
[ as 3 is not in pair ]
So, 14,283/3 = 23×23×3×3×3/3
♦ √4761
= √23×23×3×3
= 23×3
= 69
♢ Perfect sq. = 4761
________________________
ⓒ 2904
Prime factors of 2904
= 11×11×2×2×2×3
Smallest no. to be divided = 2×3 = 6
[ as 2 & 3 are not in pair ]
So, 2904/6 = 11×11×2×2×2×3/6
♦ √484
= √11×11×2×2
= 11×2
= 22
♢ Perfect sq. = 484
_______________________________
I hope this answer helps you !
_______________________________
[ first of all we need to find the prime factors of the numbers ]
ⓐ 1,800
Prime Factors of 1,800
= 5×5×3×3×2×2×2
Smallest no. to be divided = 2
[ as 2 is not in pair ]
So, 1,800/2 = 5×5×3×3×2×2×2/2
♦ √900
= √5×5×3×3×2×2
= 5×3×2
= 30
♢ Perfect sq. = 900
_______________________
ⓑ 14,283
Prime factors of 14,283
= 23×23×3×3×3
Smallest no. to be divided = 3
[ as 3 is not in pair ]
So, 14,283/3 = 23×23×3×3×3/3
♦ √4761
= √23×23×3×3
= 23×3
= 69
♢ Perfect sq. = 4761
________________________
ⓒ 2904
Prime factors of 2904
= 11×11×2×2×2×3
Smallest no. to be divided = 2×3 = 6
[ as 2 & 3 are not in pair ]
So, 2904/6 = 11×11×2×2×2×3/6
♦ √484
= √11×11×2×2
= 11×2
= 22
♢ Perfect sq. = 484
_______________________________
I hope this answer helps you !
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