Question

find the smallest number by which the number 675 must be multiplied to obtained a perfect cube
3
5
6
2
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Answer 1

$\large{\underline{\underline{Given→}}}$

Find the smallest number by which the number 675 must be multiplied to obtained a perfect cube.

$\large{\underline{\underline{Solution→}}}$

$675 = 3 \times 3 \times 3 \times 5 \times 5$

The prime factor 5 does not appear in group of three. So 675 is not perfect cube be. To make it perfect cube we need one more 5.

Hence, the smallest number by which 675 must be multiplied so that the product is a perfect cube is 5.

${\boxed{\boxed{\rm{\green{→\bar{5}✔}}}}}$

Answer 2

Answer:

mere ko lagta hai

Step-by-step explanation:

Find the smallest number by which the number 675 must be multiplied to obtained a perfect cube.

\large{\underline{\underline{Solution→}}}

Solution→

675 = 3 \times 3 \times 3 \times 5 \times 5675=3×3×3×5×5

The prime factor 5 does not appear in group of three. So 675 is not perfect cube be. To make it perfect cube we need one more 5.

Hence, the smallest number by which 675 must be multiplied so that the product is a perfect cube is 5.

{\boxed{\boxed{\rm{\green{→\bar{5}✔}}}}}

→

5

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