Question

Find the smallest number divided by 42,98,70 .step by step​

Answer 1

Answer:

2

Step-by-step explanation:

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Answer 2

Answer:

➡Firstly find the prime number factors for each number

$42 = 2 \times 3 \times 7 \\ </u></p><p><u>[tex]42 = 2 \times 3 \times 7 \\ 56 = 2 \times 2 \times7 \\ </u></p><p><u>[tex]42 = 2 \times 3 \times 7 \\ 56 = 2 \times 2 \times7 \\ 70 = 2 \times 5 \times 7$

➡The lowest common multiple will be

$2 \times 2 \times 2 \times 3 \times 5 \times 7 = 840$

➡The smallest 5 digit number is 10000.

The smallest 5 digit number is 10000.Divide 10000 by 840 and get 11.9

➡The first multiple of 840 greater than 10000 will be the 12th

$i.e. 12 \times 840 = 10080$

➡So a remainder of 3 will result if the

original number was 10083.

original number was 10083.10083/42 = 240 remainder 3

original number was 10083.10083/42 = 240 remainder 310083/56 = 180 remainder 3

original number was 10083.10083/42 = 240 remainder 310083/56 = 180 remainder 310083/70 = 144 remainder 3

Step-by-step explanation:

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