Question

Find the smallest number divisible by 15,20,24and 32 by leaving 3

Answer 1

Let us find the LCM of 15, 20, 24 and 32

15 = 3*5

20= 2*2*5

24 = 2*2*2*3

32 = 2*2*2*2*2

So LCM = 2*2*2*2*2*3*5 = 480

Next add 3 to 480 to get 483 which is the answer.

Let Check:

483/15 = 32 as quotient and 3 as remainder.

483/20 = 24 as quotient and 3 as remainder.

483/24 = 20 as quotient and 3 as remainder.

483/32 = 15 as quotient and 3 as remainder.

Answer: 483.