Math, asked by manojkumarktr9090, 9 months ago

find the smallest number divisible by 63 and 121

Answers

Answered by mhanifa

0

Answer:

7623

Step-by-step explanation:

63=3*3*7

121=11*11

LCM(63,121)=63*121=7623 which is the smallest number we are looking for

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