Question

Find the smallest number divisible by both 306 and 657

Answer 1

HCF of two number 306 and 657 is 9

to find: LCM of number

we know that ,

LCM × HCF =first number × second number

LCM ×9 = 306 × 657

LCM = 306 × 657 = 201042

= 201042 ÷ 9

=22338

Answer 2

Answer:

To Find, The smallest number which is divisible by 306  and 657, Find the L.C.M. of 306 and 657.

So,

306 = 2 × 3 × 3 × 17

657 = 3 × 3 × 73

L.C.M. of 306 and 657  = 2 × 3 × 3 × 17 × 73 = 22,338

Hence 22,338 is the smallest number which is divisible by 306 and 657.