Question

find the smallest number divisible by each of number 6,9 and 15​

Answer 1

Answer:

hope this helps :)

Step-by-step explanation:

Since, we wanted smallest perfect square number divisible by 6, 9 and 15.

calculate using LCM method

LCM = 90

But, 2 and 5 are not in pair.

Therefore, to make it perfect square no. multiply 2 × 5 to LCM (90).

= 90 × 2 × 5

= 90 × 10

= 900

Hence,

Required smallest square no. that's divisible by 6, 9 and 15 = 900

Answer 2

Answer:

90

Step-by-step explanation:

smallest number divisible is always the LCM

so LCM of 6,9,15 is (2*3*3*5) = 90

required no. is 90

hope it was helpful

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