find the smallest number is exactly divisible by 15, 20,24,32 and 36
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1
Answer:
1440
Step-by-step explanation:
LCM of 15,20,24,32 and 36 = 2 × 2 × 2 × 3 × 3 × 4 × 5 = 1440. Hence, The required Number = LCM(15,20,24,32,36) = 1440.
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1 is the answer mark as brainliest answer
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