Question

find the smallest number leaves remainder 8 and 12 when it is divided by 28 and 32 respectively ​

Answer 1

Step-by-step explanation:

we need the real numbers,so we first need to subtract the remainder from the given numbers:

28-8=20

32-12=20

As we got the required numbers now we need to find the HCF of the numbers

HCF (20,20)=20

SO 20 is the required no

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