Question

find the smallest number of 4digit which when divided by 6,8,12,20 leaves the remainder 7 in each case​

Answer 1

Answer:1011

Step-by-step explanation:

Least 4 digit number = 1000

LCM of 6,8,12 = 24

Dividing 1000 by 24 leaves a remainder 16 , Subtract 16 from 10000= 984

So this means 984 is divisible by 24

984 + 24 = 1008

Here, 1008 also divisible by 24

To find the number which leaves remainder 3, we have to add 3 to 1008

1008 + 3 = 1011

Now, 1011 is the least number of 4 digit which leaves the remainder 3 after divided by 6,8,12.

that’s all.

Answer 2

Least 4 digit number = 1000

LCM of 6,8,12,20 = 120

Dividing 1000 by 120 leaves a remainder 40 , Subtract 40 from 10000= 960

So this means 960 is divisible by 120

960 + 120 = 1080

Here, 1080 also divisible by 120

To find the number which leaves remainder 7, we have to add 7 to 1080

1080 + 7 = 1087

Now, 1087 is the least number of 4 digit which leaves the remainder 3 after divided by 6,8,12.

that’s all.