Question

find the smallest number of 5-digit which when divided by 20, 24 ,35and 45 leave 5 as remainder​

Answer 1

Answer:

10083.

Step-by-step explanation:

Least 5 digit number = 10000.

LCM(4,12,20,24) = 120

Dividing 10000 by 120 leaves a remainder 40 , Subtract 40 from 10000 = 9960

So this means 9960 is divisible by 120.

9960 + 120 = 10080.

To find the number which leaves remainder 3, we have to add 3 to 10080.

10080 + 3 = 10083.