Question

Find the smallest number of 5 digits divisible by 20,30,90.​

Answer 1

Answer:

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Find the smallest number of 5 digits divisible by 20,30,90.

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60=2×2×3×5, 90=2×5×3×3,

80=2×2×2×2×5

LCM of 60,90, and 80 =2×2×2×2×3×3×5=720

5 digit smallest no =10000

720×13=9360,10000–9360=640

10000+(720–640)=10000+80

=10080

The number is 10080.

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