find the smallest number of 5 digits that can be exactly divided by 60,90 and 80
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First ,we find the LCM of 60 ,80,90
now, we get the LCM of 60, 80, 90 =720.
The smallest number of five digits =10000
Let us divide 10000 by the LCM (720).
720)10000( 13
-720
.........
2800
-2160
............
640
The required number =10000 - remainder + LCM
=10000 - 640 + 720
= 10720 - 640
= 10080
Hence, 10080 is the smallest five digit number which is exactly divisible by 60,80,90.
now, we get the LCM of 60, 80, 90 =720.
The smallest number of five digits =10000
Let us divide 10000 by the LCM (720).
720)10000( 13
-720
.........
2800
-2160
............
640
The required number =10000 - remainder + LCM
=10000 - 640 + 720
= 10720 - 640
= 10080
Hence, 10080 is the smallest five digit number which is exactly divisible by 60,80,90.
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