Find the smallest number of 5 digits which is exactly divisible by 12, 24,48,60 and 96
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Answer:10080
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Find the smallest number of 5 digits which is exactly divisible by 12, 24,48,60 and 96
12 = 2 x 2 x 3 = 2^2 x 3
24 = 2 x 2 x 2 x 3 = 2^3 x 3
48 = 2 x 2 x 2 x 2 x 3 = 2^4 x 3
60 = 2 x 2 x 3 x 5 = 2^2 x 3 x 5
96 = 2 x 2 x 2 x 2 x 2 x 3 = 2^5 x 3
LCM (12, 24, 48, 60, 96 ) = 2^5 x 3 x 5 = 32 x 3 x 5 =96 x 5 = 480
∴ Required smallest 5-digit number which is divisible by 12, 24,48,60 and 96 = 21 x 480 = 10080
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