Math, asked by dssd2526, 1 year ago

Find the smallest number of 5 digits which is exactly divisible by 12, 24,48,60 and 96

Answers

Answered by Vishal1801
55

Answer:10080

Step-by-step explanation:

Find the smallest number of 5 digits which is exactly divisible by 12, 24,48,60 and 96​

12 = 2 x 2 x 3 = 2^2 x 3

24 = 2 x 2 x 2 x 3 = 2^3 x 3

48 = 2 x 2 x 2 x 2 x 3 = 2^4 x 3

60 = 2 x 2 x 3 x 5 = 2^2 x 3 x 5

96 = 2 x 2 x 2 x 2 x 2 x 3 = 2^5 x 3

LCM (12, 24, 48, 60, 96 ) =  2^5 x 3 x 5 = 32 x 3 x 5 =96 x 5 = 480

 ∴  Required smallest 5-digit number which is divisible by 12, 24,48,60 and 96​   =  21 x 480 = 10080

Thank you

Answered by gauravgp2503
3

Step-by-step explanation:

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