Math, asked by noorbashar859, 7 months ago

find the smallest number of 5 digits which on being divided by 30,45,and 50 leave 24,39 and 74 as reminder respectively​

Answers

Answered by muskanchhetri20
0

Answer:

The difference between the divisor and the remainder is same in all the cases which is 6

Step-by-step explanation:

How do I find the largest five-digit number which, when divided by 9, 12, 24 and 45, leaves remainders of 3, 6, 18, and 39, respectivly?

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From the info provided in the qstion we can identify that ..

The difference between the divisor and the remainder is same in all the cases which is 6

STEP 1:

LCM OF DIVISORS

LCM OF( 9,12,24,45) IS 360

STEP 2:

We know the largest five digit number is 99999

Now to find the largest five digit number which satisfy the given conditons then do the following

A) 360*N-6

N, is the quotient of 99999/360

U will get the answer as 360*277–6= 97214

B) Divide 99999/360

U will get remainder as 279

SUBTRACT 279 FROM 99999 WHICH IS 99720

Now 99720–6= 97214 which will be ur answer

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