find the smallest number of 5 digits which on being divided by 30,45,and 50 leave 24,39 and 74 as reminder respectively
Answers
Answer:
The difference between the divisor and the remainder is same in all the cases which is 6
Step-by-step explanation:
How do I find the largest five-digit number which, when divided by 9, 12, 24 and 45, leaves remainders of 3, 6, 18, and 39, respectivly?
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From the info provided in the qstion we can identify that ..
The difference between the divisor and the remainder is same in all the cases which is 6
STEP 1:
LCM OF DIVISORS
LCM OF( 9,12,24,45) IS 360
STEP 2:
We know the largest five digit number is 99999
Now to find the largest five digit number which satisfy the given conditons then do the following
A) 360*N-6
N, is the quotient of 99999/360
U will get the answer as 360*277–6= 97214
B) Divide 99999/360
U will get remainder as 279
SUBTRACT 279 FROM 99999 WHICH IS 99720
Now 99720–6= 97214 which will be ur answer