find the smallest number of 5 digits which when divided by 45 and 60 leaves remainder 7 in each case
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Step-by-step explanation:
LCM of 45 and 60 is 180.
smallest no of 5 digits =10000
Now divide 10000 by 180.
We get remaider 100.
Req no = 10000+(180-100)+7
=10000+80+7
=10087
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