Math, asked by swatisachan2584, 9 months ago

find the smallest number of 5 digits which when divided by 45 and 60 leaves remainder 7 in each case ​

Answers

Answered by manjeetyadav0011
1

Step-by-step explanation:

LCM of 45 and 60 is 180.

smallest no of 5 digits =10000

Now divide 10000 by 180.

We get remaider 100.

Req no = 10000+(180-100)+7

=10000+80+7

=10087

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