Question

Find the smallest number of 5 digits which when divided by 20,24,35 and 45 leaves 5 as remainder.​

Answer 1

Answer:

Step-by-step explanation:

5-digit no.=LCM of 20 25 35 45=2520

Remainder=5

Required no.= 2520-5

=2515

Smallest 5 digit no.=10000

Now,10000÷2515 =31