Math, asked by jaiswalpankaj04, 5 months ago

Find the smallest number of 5-digits which when divided by 20,24,35 and 45 leaves 5 as re

Answers

Answered by avnishukla1725

1

Step-by-step explanation:

find LCM

20=2×2×5

24=2×2×2×3

35=5×7

45=3×3×5

LCM=2×2×2×3×3×5×7

=2520

5 digit smallest no. is 10,000

10,000÷2520

q is 3

r is 2440

2520-2440

=80

10,000+80+5

10085

smallest 5 digit no. is 10085

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