Question

find the smallest number of 6 digit which when divided by 25 35 42 50 and 60 leaves 1 as remainder in each case​

Answer 1

Answer:

lcm of 25 35 42 50 60 is

2100.which is not a 6 dig no

so will make it a 6 digit number by multiplying required multiple.

smallest 6 digit number divisible by 2100 will be 2100×48

100800.

so for 1 to be remainder

add 1 into it

so answer will be 100801.