find the smallest number of 6912 by which of the given numbers must be multiplied so that the product is a perfect square in step-by-step
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In order to make it a perfect square, it must be divided by 3. Which is a perfect square. Therefore, the smallest number is 3
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Answer:
Prime factorization of 6912 = 2^8 * 3^3.
The prime factor 3 does not occur in pair.
In order to make it a perfect square, it must be divided by 3.
= > 6912 ÷ 3
= > 2304[48 * 48]
Which is a perfect square.
Therefore, the smallest number is 3.
Hope this helps!
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