Math, asked by QWERTYSLN5181, 9 months ago

Find the smallest number of five digits exactly divisible by 21, 28, 36, 45 division method

Answers

Answered by αηυяαg
12

Let X be the smallest number with the desired properties.

Thus X−9 is the smallest integer divisible by 21,28 36,45

Which implies that X−9 is the lcm of 21,28,36 and 45.

LCM have a distributive property.

LCM(21,28,36,45)

=LCM(LCM(21,28),LCM(36,45))

=LCM(84,180)

=1260

Thus,

Multiply 1260 by 8 we get our five digit no

X=10080

Answered by kumarikanchan0631
2

Answer:

10080

Step-by-step explanation:

1260×8

10080 is the five digits exactly divisible by 21,28,36 and 45..

HOPE IT IS HELPFUL TO YOU....

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