Find the smallest number of five digits exactly divisible by 21, 28, 36, 45 division method
Answers
Answered by
12
Let X be the smallest number with the desired properties.
Thus X−9 is the smallest integer divisible by 21,28 36,45
Which implies that X−9 is the lcm of 21,28,36 and 45.
LCM have a distributive property.
LCM(21,28,36,45)
=LCM(LCM(21,28),LCM(36,45))
=LCM(84,180)
=1260
Thus,
Multiply 1260 by 8 we get our five digit no
X=10080
Answered by
2
Answer:
10080
Step-by-step explanation:
1260×8
10080 is the five digits exactly divisible by 21,28,36 and 45..
HOPE IT IS HELPFUL TO YOU....
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