Math, asked by rahul99338, 10 months ago

Find the smallest number of five digits which leave 8 as remainder when divided by the number 54,63 and 81

Answers

Answered by abishekcps

1

Answer:

1142

Step-by-step explanation:

least number = [lcm of 54,63,81] + 8

lcm = 1134

least number =1134 +8

= 1142

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