Question

Find the smallest number of five digits which leave 8 as remainder when divided by the number 54,63 and 81

Answer 1

Answer:

Since 3410 will leave a remainder of 8 when divided by 54, 63 or 81. But our answer requires a 5 digit number. Hence we mutiply 3402 by 3 to get lowest 5 digit multiple = 10206. This number, 10206 is perfectly divisible by 54, 63 and 81 you can check.Oct 23, 2019