Math, asked by ABHI3025, 11 months ago

Find the smallest number of four digit which is divisible by 27

Answers

Answered by rajivrtp
5

Answer:

1026

Step-by-step explanation:

smallest number of four digit= 1000

again

1000/27= 37×27+1 => 37×27=999

which is 3 digit greatest no divisible by 27

then the next no= 999+27= 1026

therefore smallest four digits no that required

= 1026

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