Find the smallest number of four digit which is divisible by 27
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Answer:
1026
Step-by-step explanation:
smallest number of four digit= 1000
again
1000/27= 37×27+1 => 37×27=999
which is 3 digit greatest no divisible by 27
then the next no= 999+27= 1026
therefore smallest four digits no that required
= 1026
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