Find the smallest number of four digits which when divided by 112 and 96 leaves five as the remainder
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Answer:
Find the LCM:
112 = 2x2x2x2x7
96 = 2x2x2x2x2x3
LCM = 2x2x2x2x2x3x7 = 672
672x2+5 = 1349
The answer is 1349.
Check: 1349/112 = 12 as quotient and 5 as remainder. Correct.
1349/96 = 14 as quotient and 5 as remainder. Correct.
Step-by-step explanation:
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