Question

find the smallest number of four digits which when divided by 45 and 20 leaves no remainder​

Answer 1

Answer:

1080

Step-by-step explanation:

find LCM of 45 & 20

LCM = 180

smallest 4 digit number is 1000

1000 ÷ 180 = 5.55

hence 180 × 6 will be the smallest 4 digit number divisible by 45 & 20

180 × 6 = 1080

1080 ÷ 45 = 24

1080 ÷ 20 = 54