Question

find the smallest number of six digits exactly divisible by 3,5,7and11​

Answer 1

Answer:

1

Step-by-step explanation:

HCF(3,5,7,11)

3= 3 X 1

5= 5 X 1

7= 7 X 1

11= 11 X1

since HCF= lowest power of the common factors

HCF= 1